It's kinda like using variables, but shapes in their place. Let's set the circle to x, the triangle to y, and the square to z. Now the equations say x+(y+z)=13, (y+z)=8, and x+y=7. First thing we can do it plug 8 into the first equation for y+z, getting x+8=13. Subtract 8 to both sides and x (or circle) equals 5. Plug 5 into the last equation, x+y=7 to solve for y, getting 5+y=7. Subtract 5 to both sides and y (or triangle) equals 2. Finally, plug two in for y in y+z=8, getting 2+z=8. Subtract 2 from both sides and z (or square) equals 6. Hope I've explained it clearly!!
Answer:
6/21
Step-by-step explanation:
Brainliest?
Answer:
Can you show me the pattern?
You can find the zeros of a polynomial by first factoring it completely. Then, you use the Zero Product Property (Z.P.P) to make each term equal to zero. Finally, you just solve for the given variable, and you will have the zeros.
For example:
x²+4x+4 = 0
1. Factor The Polynomial:
(x + 2)(x + 2) = 0
2. Use Zero Product Property:
x + 2 = 0
x + 2 = 0
3. Solve for variable:
x = -2, -2
Therefore, the zeros of the polynomial are -2, -2.
Hope I explained it well and have a fantastic day!
Answer:
c. is the answer becuase since it is exterior they are talking about the outside of the parellel lines.
Step-by-step explanation:
