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3 years ago

Which of the following does not have a scale factor of 1/60? (Hint: Use Unit Conversion).

1 answer:

4 0

1in : 5ft
1in : (5 x 12) in
1in : 60 in

1ft : 20yd
1ft : (20 x 3) ft
1ft : 60 ft

1 cm : 60cm

1in : 60ft
1in : (60 x 12)in
1in : 720 in
Hence, 1in : 60ft does not have a scale factor of 1/60

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How do you write 5x - 4y = 1 in slope intercept form

Alexxandr [17]

First move the 4y to the right and the 1 to the left:

4y=5x-1

Then divide everything by 4:

y=5/4 x - 1/4

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3 years ago

Read 2 more answers

Which of the following points is a solution of y > Ixl + 5?

Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

$5 > |0|+5\\5> 0+5\\5 > 5$

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

$7 > |1| + 5\\7 > 1 + 5\\7 > 6$

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

$1 > |7| + 5\\1>7+5\\1>12$

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of $y > |x|+5$ .

Hope this helped!

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3 years ago

Does anyone need help with simple Pythagorean theorem questions?

iren2701 [21]

Answer:

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Step-by-step explanation:

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3 years ago

One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$