All categories

3 years ago

Which pair of angles are an example of alternate exterior angles?

Mathematics

2 answers:

9966 [12]3 years ago

4 0

Answer:

c. is the answer becuase since it is exterior they are talking about the outside of the parellel lines.

Step-by-step explanation:

fenix001 [56]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

A hot air balloon descends from an altitude of 2,000 feet at a constant rate of 90 feet per minute. The graph shows the altitude

liberstina [14]

Answer:

y=90x+2,000

Step-by-step explanation:

90 is the rate of change because the hot air balloon descends 90 feet per minute.

And 2,000 is the starting point because the hot air balloon started the descent at 2,000 feet.

6 0

3 years ago

Read 2 more answers

Two pounds of grapes cost 6$ what number belongs in the most right empty cell?

sdas [7]

Answer:

Table shown below

Step-by-step explanation:

Table shown below

To solve this problem let's use proportions.

If 2 pounds of grapes cost $6, half the amount will cost half the dollars, so the last row will have $3 in the price

For the second row, we know the price is $1, that is, one-sixth of the original given price. It should correspond to one-sixth of the amount of grapes or 2/6 pounds.

Simplifying the fraction, we get 1/3 or 0.33 pounds

6 0

3 years ago

Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.

kykrilka [37]

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4) so 2 x 2 x 5 x 4 = 80.

5 0

2 years ago

Solve the following:<br> a.) X^2 - 2x – 24 = 0<br><br> b.) x^2 - 11x + 18 =0

wolverine [178]

Answer:

The answer for the first equation is,

X = 6, -4

The answer for second equation is,

X = 9,2

7 0

2 years ago

Read 2 more answers