61 = 3b + 7
3b + 7 = 61
3b = 61 - 7
3b = 54
b = 54/3
b = 18.
Step-by-step explanation:
Use the first fundamental theorem of calculus.
∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0
C i think if I’m not mistaken
Answer:
it's 1/3
Step-by-step explanation:
5/6+(-1/2)
5/6-1/2
LCM= 6
(5-3)/6
2/6
1/3
X^3 - h^3 + 8 because you cube the variables as well as 2, and 2x2x2=8.
