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ZanzabumX [31]
3 years ago
15

Evaluate:

Mathematics
1 answer:
Anni [7]3 years ago
4 0

Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says \sqrt[3]{x \times x \times x} = x   -----(A)

Also

\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y   ---(B)

Now let us see each part one by one

a) we have

\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}

Now 64 = 4 x 4 x 4

0.027 = 0.3 x 0.3 x 0.3

0.008 = 0.2 x 0.2 x 0.2

substituting these values

\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}

Applying Rule A in above

=4+0.3+0.2

=4+0.5

4.5

b) we have \sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}

Applying the B rule in this

=0.3 \times 11

3.3

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One number is twelve greater than another number. Twice the larger plus five times the smaller is 38. Find both numbers.
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Answer:

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3 years ago
What function translates the function f(x) = to the right 2 units and up 10 units?<br><br> g(x)= |
Mandarinka [93]

Answer:

g(x) = | x - 2 | + 10

Step-by-step explanation:

given g(x) then g(x± h ) is a horizontal translation of g(x)

• if h > 0 then a move to the left of h units

• if h < 0 then a move to the right of h units

here the move is 2 units to the right, then

g(x) = | x - 2 |

given g(x) then g(x) + c is a vertical translation of g(x)

• if c > 0 then a move up

• if c < 0 then a move down

here the move is 10 units up , then

g(x) = | x - 2 | + 10

8 0
1 year ago
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the first three are irrational


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2 years ago
What is m∠2 + m∠3?<br> HELPPPPP!!!!!
Eva8 [605]
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5 0
3 years ago
Read 2 more answers
getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0
3 years ago
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