Question

Find the vertex for the function e="g(x)=2x^{2} +12-16" alt="g(x)=2x^{2} +12-16" align="absmiddle" class="latex-formula">

Answer 1

Answer:

(-3, -34)

Step-by-step explanation:

I'm assuming g(x) is supposed to by g(x) = 2x² + 12x - 16

The general form for a quadratic function is f(x) = ax² + bx + c

For our equation, a = 2, b = 12 and c = -16

The formula for the x coordinate of the vertex is

x = -b/(2a)

Plug in our values and simplify...

x = -12/(2*2) = -12/4 = -3

Plug that value into g(x) to find the y coordinate of the vertex:

g(-3) = 2(-3)² + 12(-3) - 16

  g(-3) = 2(9) - 36 - 16

     g(-3) = -34