Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
18 = 10 + 2k
move 10 to the other side
sign changes from +10 to -10
18-10=10-10+2k
18-10= 2k
8= 2k
divide by 2 to get k by itself
8/2= 2k/2
Cross out 2 and 2 , divide by 2 and then becomes 1*1*k= k
k=8/2
Answer: k= 4
Im so confused by this question but my only guess would be that since a coin is a 1/2 chance getting it heads twice is 1/2 * 1/2 which is 1/4 so the person who best they can get 2 heads in a row pays 1/4 of the bet being 5 dollars because 1/4 of 20 is 5 and the person who bets that they can't get two heads pays 15 dollars because that is 3/4 of the bet
tldr: 1/4 chance to get heads pays 1/4 of bet 5$
3/4 chance not to get heads pays 3/4 of bet 15$