With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
<h3>What is the surface area of a truncated prism?</h3>
The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:
A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)
A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²
A = 276 cm²
With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
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Answer is <
Why? 1/4 is smaller than 1/2
1/4 can be 4 slices while 1/2 can be 2 slices
2 slices > 4 slices
X= 7/93 or roughly 0.07526...
Area of a triangle:
A (triangle )= 4 · 6 / 2 = 12 ft²
150 - 12 = 138 ft² ( the maximum area of the rectangle )
L = ?
W = 6 ft
A ( rectangle ) = L · W
L · 6 = 138
L = 138 : 6 = 23 ft.
Answer: the maximum length of the base of the rectangle he can build is 23 ft.
