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umka2103 [35]
2 years ago
8

What is the BEST estimate of the expression 398 divided by 9.9 times 1 5/6 plus (-22)

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
4 0

Answer:

51.7037037037

Step-by-step explanation:

But estimated, probably 51.7 or 52

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PLEASE HELP!!!!!!!!!!
kolbaska11 [484]
11/18 =0.6111111. I don’t think the ! Has any meaning
3 0
1 year ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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3 years ago
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What is 60 divided by 5 +1 X(12-6)? ....(step by step)what to do
natita [175]

Answer:

5.455

Step by step explanation

Going by BODMAS

Bracket=(12-6)=6

Multiplication =(1*6)=6

Addition=(5+6)=11

Therefore; 60/11=5.455

5 0
3 years ago
If a(9,18) and b(1,12) find
galina1969 [7]
AB= \sqrt{(9-1)^2+(18-12)^2} = \sqrt{8^2+6^2}= \sqrt{64+36} = \sqrt{100}=10
6 0
3 years ago
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