I think it would be 64/100 because 64 percent is most likely out of 100 percent
Answer:
10
Step-by-step explanation:
10. ................ ..........
Answer:
1716 ways
Step-by-step explanation:
Given that :
Number of entrants = 13
The number of ways of attaining first, second and third position :
The number of ways of attaining first ; only 1 person can be first ;
Using permutation :
nPr = n! ÷(n-r)!
13P1 = 13! ÷ 12! = 13
Second position :
We have 12 entrants left :
nPr = n! ÷(n-r)!
12P1 = 12! ÷ 11! = 12
Third position :
We have 11 entrants left :
nPr = n! ÷(n-r)!
11P1 = 11! ÷ 10! = 11
Hence, Number of ways = (13 * 12 * 11) = 1716 ways
Answer:
See I don't know the Answer but I Need points to ask question so Sorry
Step-by-step explanation:
D the rest would be impossible to recreate