(5x+2y=23 (13x+3y=51
1 answer:
Answer:
Step-by-step explanation:
{5x + 2y = 23
{13x + 3y = 51
−5⁄13[13x + 3y = 51]
{5x + 2y = 23
{−5x - 1 2⁄13y = 19 8⁄13 >> New Equation
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11⁄13y = 3 5⁄13
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11⁄13 11⁄13
[Plug this back into both equations above to get the x-coordinate of 3];
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Answer:
:)
Step-by-step explanation:
For simplicity I will substitue for β.
In the first step I used the identity
And I factored out
Then it's just simple algebra to cancel till the 3rd step where we used another identity derived from the Pythagorean Theorem.
That's it!