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Brums [2.3K]
4 years ago
11

Find angle ABC 8x+16+6x-60=180

Mathematics
1 answer:
kykrilka [37]4 years ago
8 0
Collect like terms so that the equation becomes 14x-44=180
Move negative 44 to the other side as a positive so equation becomes
14x=224
Divide both sides by 14
224/14 which is 16
So x is equal to sixteen
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A person earns $43200.00 one year and receives an 8% raise in salary. what is the new salary?
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46,656. 43,200 x 1.08
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3 years ago
Shreman drew a shape with these properties: •Four sides •Four right angles •Two sides have different lengths​
yarga [219]

Answer: the shape is a rectangle

Step-by-step explanation:

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3 years ago
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What is the value of b?
astra-53 [7]

Answer:

Step-by-step explanation:

The line has two clear points (6,10) and (2,2)

y=mx+b

m=(y2-y1)/(x2-x1)

m=(2-10)/(2-6)=-8/-4=2 so far our line is

y=2x+b, using point (2,2) we can solve for b

2=2(2)+b

2=4+b

b=-2 so our line is

y=2x-2, and we want to know the coordinates for (4,b)

b=2(4)-2

b=8-2

b=6

Now we want to know the coordinates for (a,8)

8=2a-2

10=2a

a=5

5 0
3 years ago
Hüseyin draws a fox with a scale of 3 units on his graph paper represents 15cm. The fox has an actual height of 80cm. What is th
Over [174]

Answer:

The height of the fox in Huseyin's drawing is, 16 units

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

As per the statement: Huseyin draws a fox with a scale of 3 units on his graph paper represents 15 cm. The fox has an actual height of 80 cm.

⇒ We are given Scale of 3 units.

On graph paper the length of fox is 15 cm.

The fox has an actual height = 80 cm

let x be the height in units of the fox in Huseyin's drawing.

By definition of proportion;

\frac{3}{15} = \frac{x}{80}

by cross multiply we get;

3 \times 80 = 15x

Simplify:

240 = 15x

Divide both sides by 15 we get;

x = 16 units.

Therefore, the height of the fox in Huseyin's drawing is, 16 units


6 0
3 years ago
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Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square
S_A_V [24]

Answer and Explanation:

Given : Sides of right triangle 5,12 and 13.

To find : Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square ?

Solution :

If 5,12 and 13 are sides of a right angle triangle then

13 is the hypotenuse as it is largest side.

then we take perpendicular as 12 and base as 5.

The area of the right angle triangle is

A=\frac{1}{2}\times b\times h

Here, h=12 and b=5

A=\frac{1}{2}\times 5\times 12

A=5\times 6

A=30

The area of the right angle triangle is 30 units.

30 is not a perfect square as 30=2\times 3\times 5

There is no square pair formed.

3 0
3 years ago
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