Answer:
42°
Step-by-step explanation:
angle 3 + angle 4 = 180° because together they make a straight line. So your equation should be 23x + 7x = 180. Add the like terms and you get 30x=180. Divide by 30 on both sides to get x. now you know that x=6. angle 4 = 7x. so you would multiply 7*6 to get 42. Thus angle 4= 42°
In 2 years :
b(x) = 7x + 75....b(2) = 7(2) + 75.....b(2) = 14 + 75....b(2) = 89
c(x) = 75(1.06)(2)...c(x) = 79.5 * 2 ....c(x) = 159
in 12 years :
b(x) = 7x + 75...b(12) = 7(12) + 75....b(12) = 84 + 75....b(12) = 159
c(x) = 75(1.06)(12)....c(12) = 79.5 * 12....c(12) = 954
c(x) has the highest value in both 2 and 12 years
1. Put the numbers in order from smallest to largest, e.g. 2, 6, 12, 18, etc.
Range:
To work out the range take the biggest number and the smallest number and subtract them from each other… e.g. 18-2=16 so the range is 16
Mean:
Add all the numbers together and divide by how many of them there is, e.g. 2+6+12+18=38/4=9.5 so the mean is 9.5
Median:
Again make sure the numbers are in order from smallest to biggest, start crossing out the first number then the last number then the second then the second to last until you get the middle number, e.g.-2-, 6, 12, -18- …. Since I have two numbers in the middle to find the median you have to find the number in between them, if it’s easy to spot like 5, 6 would be 5.5 you can just find it by looking but if there’s a large difference like the 6, 12 in my made up sequence just add the 2 number together and divide by 2 e.g. 6+12=18/2= 9 so the median is 9
(If there’s only one number it’s just that one number)
Mode:
Mode is the number that occurs the most, for example 2, 6, 12, 18 hasn’t got a mode but if it was 2, 6, 6, 12, 12, 12, 18
The mode would be 12 because there’s the most of it, 3 while only two 6s, one 2 and one 18.
Hope this helps! I would’ve done the answers for you but I couldn’t see the whole sequence. Good luck! :)
You have to do pemdas (please excuse my dear aunt sally ) which are Parentheses, exponents, multiplication, division, subtraction.
