Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
100x14=1400
1400 divided by 15=93.3
So your grade would still be a low A
Answer:
13.708
Step-by-step explanation:
Answer:
See the three attached images.
Step-by-step explanation:
image1 shows the intersection of b and c: 
. (green "football")
image2 shows the <u>complement</u> of a (outside a): 
(yellow)
image3 shows the intersection of those sets: 
(green "football with a bite out of it") :-)
Answer:
3.
Step-by-step explanation:
The graph is being moved to the left and then stretched by a factor of three. If it were to be compressed than the 3 would be 1/3.
