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3 years ago

Please help me

Mathematics

2 answers:

KiRa [710]3 years ago

3 0

Answer:

Step-by-step explanation:

To sum the 2 expressions collect like terms

4x² - 5x + 3 + 2x² + 7x - 8

= (4x² + 2x² ) + (- 5x + 7x ) + (3 - 8 )

= 6x² + 2x + (- 5)

=6x² + 2x - 5 → a

maks197457 [2]3 years ago

3 0

Answer:

option a is correct.

Step-by-step explanation:

To find the sum of given two expressions,we add coefficients of $x^{2}$ , $x$ and constant

$(4+2)x^{2} +(-5+7)x+(3-8)$

$(6)x^{2} +(2)x+(-5)$

$6x^{2} +2x-5$ which is the correct answer

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Determine the critical value or values for a one-mean z-test at the 1% significance level if the hypothesis test is right-tailed

kifflom [539]

Answer:

We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:

Null hypothesis: $\mu \leq \mu_o$

Alternative hypothesis: $\mu > \mu_o$

For this case the significance is 1%. So we need to find a critical value in the normal standard distribution who accumulates 0.99 of the area in the left and 0.01 in the right and for this case this critical value is:

$z_{crit}= 2.326$

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\sigma$ represent the standard deviation for the population

$n=$ sample size

$\mu_o$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:

Null hypothesis: $\mu \leq \mu_o$

Alternative hypothesis: $\mu > \mu_o$

$z_{crit}= 2.326$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If

vesna_86 [32]

Answer:

<h2>The probability is 58 %.</h2>

Step-by-step explanation:

This problem belong to a normal distribution probability.

Mean = 63.6

Standard Deviation = 2.5.

We have to find the probability of a height greater than 63.0.

Due to the normal probability, we need to find the Z score first:

$Z=\frac{x-u}{o}$ ; where x is the height, u is the mean, and o is the standard deviation.

$Z=\frac{63-63.6}{2.5} \\Z= -0.24$

Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.

But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,