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Maslowich
3 years ago
15

The administrative assistant at a software company often provides breakfast when there is a morning meeting. For last week's sal

es meeting, she purchased 6 dozen doughnuts and 2 dozen croissants, spending a total of $50. In preparation for yesterday's safety meeting, she spent $43 on 6 dozen doughnuts and 1 dozen croissants. Assuming she purchased the items at the same bakery both times, how much does a dozen of each cost?
Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

1 dozen donuts=$6

1 dozen  croissants=$7

Step-by-step explanation:

50-43=7

dozen croissants =$7

50-14=36

36÷6=6

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Help pleasee!
victus00 [196]

Answer:

  1. Corresponding Angle Postulate
  2. Corresponding Angle Postulate
  3. Reflexive Property
  4. Similar

Step-by-step explanation:

The pairs of angles referenced in statements 1 and 2 are "corresponding" angles, so the Corresponding Angle Postulate applies.

The Reflexive Property is what says something is the same as itself. This is used in statement 3.

The upshot of the AA Similarity postulate is to say triangles are similar (as in statement 4).

7 0
2 years ago
find a model for simple harmonic motion if the position at t = 0 is 6, the amplitude is 6 centimeters, and the period is 4 secon
Y_Kistochka [10]

Answer:

y = 6cos(π/2)t

Step-by-step explanation:

Given in the question that,

in a simple harmonic motion in which

at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.  

And,

the period is given as 4 sec

We know that model equation of simple harmonic motion is

<h3>y = a. cosb(t + c) + d</h3>

here,

a is amplitude

c is Horizontal shift or phase shift

d is Vertical shift

<h3>Step1</h3><h3>Find b</h3>

Period = 2 π / b

4 = 2π / b

b = 2π/4

b = 1π/2

<h3>Step2</h3><h3>Find shifts</h3>

Horizontal and vertical shifts are 0.

So, c = 0 and d = 0

<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>

y = 6cos π/2 (t + 0) + 0

y = 6cos(π/2)t

4 0
4 years ago
A thermometer is taken from a room where the temperature is 20◦C to the
lord [1]

Answer:

a) T(2) = 8.265: at time t = 2 minutes the temperature will be 8.265 degress

b) 6 = T(3.55): the temperature will be 6 degrees at time t = 3.55 minutes.

Step-by-step explanation:

When dealing with temperature changes, it's best to work with Newton's Law of Cooling.

T(t) = T_s + Ce^{kt}

here:

T(t) : the temperature in the room.

T_s : ambient (or outdoor) temperature (that always remains constant, in our case: T_s = 5 )

C\,\text{and}\,k: are constants

Our conditions are provided:

1) T(0) = 20

2) T(1) = 12

using the first condition

T(0) = 5 + Ce^{k(0)}\\20 = 5 + C(1)\\C = 15

using the second condition:

T(1) = 5 + Ce^{k(1)}\\12 = 5 + Ce^{k}\\e^k = \dfrac{7}{C}

we can use our calculated value of C to find k

e^k = \dfrac{7}{15}\\k = \ln{(\dfrac{7}{15})}\\k = -0.7621

Finally we can put these constants back in the main equation:

T(t) = T_s + Ce^{kt}

T(t) = 5 + 15e^{-0.7621t} or T(t) = 5 + 15e^{\ln{(\frac{7}{15})t}

a) Reading after one more minute?

so it's asking:

T(2) = ?

T(2) = 5 + 15e^{\ln{(\frac{7}{15})(2)}}\\T(2) = \dfrac{124}{15} \approx 8.267

Hence, after one more minute the temperature of the room will be 8.267 degrees

b) When will it be 6 degrees?

T(t) = 6?

6 = 5 + 15e^{-0.7621t}\\\text{and solve for $t$}\\\\\dfrac{6-5}{15}=e^{\ln{(\frac{7}{15})}t}\\\ln{\left(\dfrac{1}{15}\right)} = \ln{\left(\dfrac{7}{15}\right)t}\\\ln{\left(\dfrac{1}{15}\right)} \div \ln{\left(\dfrac{7}{15}\right)} = t \approx 3.55\\

Hence at t = 3.55 minutes the temperature of the room will be 6 degrees.

8 0
3 years ago
PLEASE HELP ME!! 100 points
Yakvenalex [24]
Square root (8-0)^2 + (8+7)^2

square root 64+15^2

=8+15
= 23
8 0
4 years ago
Read 2 more answers
American households increasingly rely on cell phones as their exclusive telephone service. It is reported that 53.0% of American
FrozenT [24]

Solution :

a). According to the reports, 53.0% of the American households still have a landline phone service. Out of which 8 households are randomly called.

Here, the landline phone service is p = 53.0%

                                                           n = 8

Therefore, q = 1 - p

                     = 1 - 0.53

                     = 0.47

here we use the binomial distance because the probability of having the landline phone service is constant and the number of the trial are finite.

b). Let x be the number of household in the sample group having landline phone service.

  Probability that none of the household in the sample group have a landline service is

= P( x = 0)

$=^8C_0 (0.53)^0(0.47)^8$

= 0.002 (using the binomial calculation )

c). Probability that exactly 5 of the household in the sample have a landline service is given by :

 P(x = 5)

$=^8C_5 (0.53)^5(0.47)^3$

= 0.24

8 0
3 years ago
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