Answer:
2/3 1/2 3/4 5/6
Step-by-step explanation:
anything that isnt 1/3 or equal to it is an answer
Answer:
Step-by-step explanation:
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) = 
P(B) = 
P(AUB) = 0.68 =

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
=P(A'UB') = P(AB)'
=
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Answer:
The answer should be y=2.5