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2 years ago

Write an equation to match the story and diagram below. Solve for X in the equation

Mathematics

1 answer:

MrMuchimi2 years ago

7 0

Answer:

x = 11

Step-by-step explanation:

15 + 22 + 16 + x + x = 75

53 + 2x = 75

2x = 22

x = 11

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Solve the system algebraically. Check your work.

Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10 (1)

And 3x+2y=63x+2y=6 (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30 (3)

15x+10y=3015x+10y=30 (4)

Now subtract (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0

3 years ago

ANSWER QUICK <br> 13+5 3/4

Vaselesa [24]

Answer:

18.75 or 18 3/4

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A pen in the shape of an isosceles right triangle with legs of length x ft and hypotenuse of length h ft is to be built. If fenc

Vaselesa [24]

Answer:

$\frac{8h}{\sqrt{2}} + 16h$

Step-by-step explanation:

First we need to compute the side length as a function of h

So x be the side length of the right isosceles triangle, in Pythagorean formula we have

$x^2 + x^2 = h^2$

$2x^2 = h^2$

$x = \frac{h}{\sqrt{2}}$

The cost for the legs is

$C_l = 4*2x = \frac{8h}{\sqrt{2}}$

The cost for the hypotenuse is

$C_h = 16h$

So the total cost in term of h is

$C = C_l + C_h = \frac{8h}{\sqrt{2}} + 16h$

5 0

3 years ago

I do not understand the final part of this question?

jolli1 [7]

AB=CD (given)

AB=AM+DM (M is mied point of AB&CD

CD can be writen as AM+DM)

8 0

2 years ago

Write an equation for a line perpendicular to y=3x+1 and passing through the point (6,2)

Ymorist [56]

Answer:

$y = -\frac{1}{3}x + 4$

Step-by-step explanation:

Required

Equation of line

passes through $(6,2)$

In an equation of the form $y =mx + b$ ; the slope is $m$

So, by comparison;

The slope of $y = 3x + 1$ is: $m =3$

From the question, we understand that the required equation is perpendicular to $y = 3x + 1$

This means that its slope is:

$m_2 =-\frac{1}{m}$

So, we have:

$m_2 =-\frac{1}{3}$

The line equation is:

$y = m_2(x - x_1) + y_1$

Where:

$(x_1,y_1) = (6,2)$

So, we have:

$y = -\frac{1}{3}(x - 6) + 2$

$y = -\frac{1}{3}x + 2 + 2$

$y = -\frac{1}{3}x + 4$

3 0

2 years ago