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posledela
3 years ago
6

Write an equation to match the story and diagram below. Solve for X in the equation

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

15 + 22 + 16 + x + x = 75

53 + 2x = 75

2x = 22

x = 11

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Hey can you please help me with this
Tasya [4]

x=-11

Hope this helps :T

8 0
3 years ago
Mr. Caldwell divides 72 students into 12 groups. Solve the equation 72/s =12 find the number of students in each group.
RideAnS [48]

Answer:

6

Step-by-step explanation:

72 divided by grops of 12 so 72/12 =6

3 0
3 years ago
Read 2 more answers
Triangle ABC is to be dilated through point P with a scale factor of 3. How many units away from point A along ray PA will A’ be
drek231 [11]

Answer:

A' will be located 10 units from point A along ray PA

Step-by-step explanation:

we know that

The scale factor is equal to 3

To obtain PA', multiply PA by the scale factor

so

PA'=PA*3

PA=5 units

substitute

PA'=(5)*3=15 units

AA'=PA'-PA=15-5=10 units

therefore

A' will be located 10 units from point A along ray PA

3 0
3 years ago
Read 2 more answers
What is 6285 divided by 89?
dalvyx [7]
The answer to the question is <span>70.6179775281. which also can be converted to 71.</span>
7 0
3 years ago
Read 2 more answers
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
2 years ago
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