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3 years ago

Part 2

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

Answer:

$\displaystyle f(t) = -16t^2 + 192t; Maximum$

Step-by-step explanation:

Maximum Value → Parabola opens downward [<em>−A</em>]

Minimum Value → Parabola opens upward [<em>A</em>]

<em>See graph above</em>

I am joyous to assist you anytime.

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Find the nth term of the arithmetic sequences<br> a1=5,d=6,n=11

ki77a [65]

here's the solution,

n = 11
a = 5 ( a = first term )
d = 6 ( d = common difference )

we know,

=》

$nth \: \: term \: = a \: + (n - 1) \times d$

=》

$11th \: \: term = 5 + (11 - 1) \times 6$

=》

$11th \: \: term = 5 + (10 \times 6)$

=》

$11th \: \: term = 5 + 60$

=》

$11th \: \: term = 65$

nth term ( 11th term ) = 65

3 0

3 years ago

HELP ME PLEASE, i will give brainliest

max2010maxim [7]

Based on the right angle triangle and the given parameters, cos K = 5/13

<h3>Trigonometric ratios</h3>

sin = opposite / hypotenuse

cos = adjacent / hypotenuse

Tan = opposite / adjacent

Given parameters:

Hypotenuse = 13
Adjacent = 5
Opposite = 12

Therefore,

cos K = adjacent / hypotenuse

cos K = 5/13

Learn more about right triangle:

brainly.com/question/2217700

#SPJ1

6 0

2 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

4 years ago

What's the answer to this equation?

Serggg [28]

The answer is 5b²/6c

Ok so you just have to simplify
15/18 = 5/6 (cause 3*5=15 and 3*6=18)

Then you do as the picture above says.

5 0

4 years ago

Hallar la medida en radianes de 150 grados

nlexa [21]

150 degrees =
2.618 radians

3 0

3 years ago