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Masteriza [31]
3 years ago
7

What is 6 divide by 2 times 3 times 100 multiply by 700 and divide by 1.37 and multiply by 0.778 and then add 0.778913 times 100

time 10 time 1.77 then multiply by 444444.47 then divide by 7777777.0999 and then add 100.
MUST BE CORRECT OR I WILL REPORT YOU!!!
Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer:

~460032.8

Step-by-step explanation:

Essentially, when this is written out, we get:

6 ÷ 2 × 3 × 100 × 700 ÷ 1.37 × 0.778 + 0.778913 × 100 × 10 × 1.77 × 444444.47 ÷ 7777777.0999 + 100

Order of operations says to do multiplication and division first, so let's calculate 6 ÷ 2 × 3 × 100 × 700 ÷ 1.37 × 0.778 separately:

6 ÷ 2 = 3

3 × 3 = 9

9 × 100 = 900

900 × 700 = 630000

630000 ÷ 1.37 = 459854

459854 × 0.778 = 357766

Now calculate 0.778913 × 100 × 10 × 1.77 × 444444.47 ÷ 7777777.0999:

0.778913 × 100 × 10 × 1.77 × 444444.47 = 612744929

612744929 ÷ 7777777.0999 ≈ 78.78

Add these all up:

357766 + 78.78 + 100 ≈ 460032.8

ddd [48]3 years ago
5 0

Answer:

20622.58008

Step-by-step explanation:

6 divide by 2: 3

times 3: 9

times 100: 900

multiply by 700: 630000

divide by 1.37: 459854.0146

multiply by 0.778: 357766.4234

then add: 0.778913 × 100 × 10 × 1.77:

359145.0994

multiply by 444444.47: 1.5962 ×10¹¹

divide by 7777777.0999: 202522.58008

add 100: 20622.58008

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7 0
3 years ago
Roll one fair, six-sided die, numbered 1 through 6. Let A be the event you will roll an even number. Let B be the event you will
11111nata11111 [884]

Answer:

a) not independent

b) not mutually exclusive

Step-by-step explanation:

Given:

- A 6 sided die is rolled

- Event A is rolling an even number

- Event B is rolling a prime number

Find

- (a) Are A and B independent events?

- (b) Are A and B mutually exclusive events?

Solution:

- We will find the probability of each event:

                       set(Even number: A) = {2, 4, 6} = 3 outcomes

                       set(Prime number: B) = {2 , 3, 5} = 3 outcomes

- The probabilities are:

                        P(A) = 3/6 = 0.5

                        P(B) = 3/6 = 0.5

- For Event A and B to be independent then the following condition must match:

                        P ( A & B ) = P(A)*P(B)

                        set (A&B) = {2} = 1 outcome

                        P(A&B) = 1/6

                        1 / 6 = 0.5*0.5

                        1/6 = 0.25         ...... NOT INDEPENDENT

- For Event A and B to be mutually exclusive then the following condition must match:

                        P(A&B) = 0

                        P(A&B) = 1/6

Hence, we can say the events are NOT MUTUALLY EXCLUSIVE

7 0
3 years ago
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