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GaryK [48]
3 years ago
8

Factor Completely. 3x^2-30x+63

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

The correct answer is,

3x² - 30 x + 63 = 3(x - 3)(x - 7)

Step-by-step explanation:

The given polynomial is 3x² - 30 x + 63

<u>Factorization of 3x² - 30 x + 63</u>

<u>Splitting method</u>

3x² - 30 x + 63 = 3(x² - 10 x + 21)      (taking 3 as common)

= 3(x² - 3 x  - 7x + 21)        (middle term splitting)

= 3[x (x - 3) -7(x - 3)]           (taking x and -7 as common)    

= 3[(x - 3)(x - 7)]

Therefore 3x² - 30 x + 63 = 3(x - 3)(x - 7)

The correct answer is 3(x - 3)(x - 7)

N76 [4]3 years ago
3 0

Answer:

3(x-3)(x-7)

Step-by-step explanation:

We have given a expression.

3x²-30x+63

We have to calculate the factor of given expression.

taking 3 common from given expression, we have

3(x²-10x+21)

Splitting the middle term of given expression, we have

3(x²-3x-7x+21)

Making groups , we have

3(x(x-3)-7(x-3))

Taking (x-3) as common, we have

3(x-3)(x-7) which is the answer.

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Please help
Schach [20]

Answer:

Hence, option: B is correct (11.02 seconds)

Step-by-step explanation:

Spencer hits a tennis ball past his opponent. The height of the tennis ball, in feet, is modeled by the equation h(t) = –0.075t2 + 0.6t + 2.5, where t is the time since the tennis ball was hit, measured in seconds.

Now we are asked:

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i.e. we have to find the value of t such that height is zero i.e. h(t)=0.

-0.075t2+0.6t+2.5=0

or 0.075t^2-0.6t-2.5=0

i.e. we need to find the roots of the above quadratic equation.

on solving the equation we get two roots as:

t≈ -3.02377 and t≈11.0238

As time can't be negative; hence we will consider the value of t as t≈11.0238.

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7 0
3 years ago
Read 2 more answers
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

3 0
3 years ago
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