5/6= c/9
Cross mutiple. 5* 9= 45 . c*6
45= 6c
divide by 6 for 45 and 6c
45/6= 6c/6
45/6= c
Reduce 45/6. Divide by 3
45/3, 6/3
15/2= c
Answer: c= 15/2 or in decimal form , c= 7.5
Length (L): w + 3 ⇒2(w + 3)
width (w): w ⇒ w - 1
Area (A) = L x w
A = (w + 3)(w)
A = w² + 3w
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A + 176 = 2(w + 3)(w - 1)
(w² + 3w) + 176 = 2(w + 3)(w - 1)
w² + 3w + 176 = 2w² + 4w - 6
3w + 176 = w² + 4w - 6
176 = w² + w - 6
0 = w² + w - 182
0 = (w - 13) (w + 14)
0 = w - 13 0 = w + 14
w = 13 w = -14
Since width cannot be negative, disregard -14
w = 13
Length (L): w + 3 = (13) + 3 = 16
Answer: width = 13 in, length = 16 in
Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.
Answer:
(a) Circle Q is 9.4 units to the center of circle P
(b) Circle Q has a smaller radius
Step-by-step explanation:
Given
Solving (a): The distance between both
The equation of a circle is:
Where
P and Q can be rewritten as:
So, for P:
For Q:
The distance between them is:
Where:
--- 
--- 
So:
Solving (b): The radius;
In (a), we have:
--- circle P
--- circle Q
By comparison
<em>Hence, circle Q has a smaller radius</em>
