In a histogram, the highest bar is the mode, which means the number the bar represents appears the most.
The answer would be D. Three, because it appears most often.
One hundred eighty-seven and twenty-three thousandths
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A=-.25+6.7t, s=.75+4.5t when Amir catches up a=s so:
-.25+6.7t=.75+4.5t add .25 to both sides
6.7t=1+4.5t subtract 4.5t from both sides
2.2t=1 divide both sides by 2.2
t=10/22 hr
t≈0.45 hr (to nearest hundredth)
I got 9.75 hope it's right
1080 is correct hope this helps.
