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3 years ago

Your fraction card is 10/10 what are some ways you could move?

Mathematics

1 answer:

devlian [24]3 years ago

6 0

Answer:

10/10 on two tracks ⇒ 1/2 + 5/10

10/10 on three tracks ⇒ 1/2 + 1/10 + 4/10

10/10 on four tracks ⇒ 3/10 + 2/10 + 1/10 + 4/10

Step-by-step explanation:

As 10/10 is the fraction card. We can move it in many ways.

10/10 on two tracks ⇒ 1/2 + 5/10

10/10 on three tracks ⇒ 1/2 + 1/10 + 4/10

10/10 on four tracks ⇒ 3/10 + 2/10 + 1/10 + 4/10

Verification:

10/10 on two tracks ⇒ 1/2 + 5/10

As LCM is 10

10/10 on two tracks ⇒ 1/2 + 5/10 = (5 + 5)/10 = 10/10

10/10 on three tracks ⇒ 1/2 + 1/10 + 4/10

As LCM is 10

10/10 on three tracks ⇒ 1/2 + 1/10 + 4/10 ⇒ (5 + 1 + 4)/10 = 10/10

10/10 on four tracks ⇒ 3/10 + 2/10 + 1/10 + 4/10

As LCM is 10

10/10 on 4 tracks ⇒ 3/10 + 2/10 + 1/10 + 4/10 ⇒ (3 + 2 + 1 + 4)/10 = 10/10

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Answer:

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So the best answer for this case would be:

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Step-by-step explanation:

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Solution to the problem

Let X the random variable that represent the costs of unleaded gasoline of a population, and for this case we know the distribution for X is given by:

$X \sim N(4.09,0.08)$

Where $\mu=4.09$ and $\sigma=0.08$

We select a sample size of n =16. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 4.09$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}= \frac{0.08}{\sqrt{16}}= 0.02$

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Answer:

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Step-by-step explanation:

Given

Granny Smiths = 23

Honey Crisp = 14

Red Delicious = 31

Required

- Probability of Pulling out one of each

- Probability of Pulling out 4 Honey Crisp; 2 Granny Smiths; 1 Red Delicious

First, the total number of apple needs to be calculated.

Total = Granny Smiths + Honey Crisp + Red Delicious

Total = 23 + 14 + 31

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Similarly,

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= P(Granny) * P(Granny)

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