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pochemuha
2 years ago
13

HELP ALSO CHECK OUT MY OTHER QUESTION THERE BOTH 20 POINTS!!!

Mathematics
1 answer:
4vir4ik [10]2 years ago
5 0

Answer:

D. 10 3/8

Step-by-step explanation:

First make them into a improper fraction

\frac{29}{8} +\frac{27}{4}

Find the lowest common denominator:

\frac{29}{8} +\frac{27*2}{4*2}

Multiply the denominators:

\frac{29}{8} +\frac{27*2}{8}

Multiply the numerators:

\frac{29}{8} +\frac{54}{8}

Combine the fractions:

\frac{(29+54)}{8}

Combine the numerators:

\frac{83}{8}

=

10\frac{3}{8}

Hence, D. 10 3/8 is the Correct answer.

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If no (A) = 40%, no (B) = 30%, n (A∩B) = 20% then find n (<br> (A B)<br> using formula.
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Answer:

solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).

Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,

n(A∪B)=n(A)+n(B)−n(A∩B)

⇒40=20+30−n(A∩B)

⇒40=50−n(A∩B)

⇒n(A∩B)=50−40

⇒n(A∩B)=10

Hence, n(A∩B)=10

Step-by-step explanation:

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