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2 years ago

I just need a quick small response for this.

Mathematics

1 answer:

Degger [83]2 years ago

5 0

Answer:

the process of isolating a variable in these literal equations is similar to solving a one-step equation because after isolating a variable you solve the rest of the equation,it is different from solving a one-step equation because it is more than one step so it takes longer to solve

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Find the midpoint of the following segment created by these pairs of endpoints: (0, 1), (0, 5)

lyudmila [28]

I believe it is 1, but i'm not completely sure.

4 0

3 years ago

Read 2 more answers

Our pool is twice as long as it is wide and is surrounded by a walkway of uniform width of 1 foot. The

Zigmanuir [339]

Step-by-step explanation:

x=width of pool

2x=length of pool

the dimensions of the rectangle forming the walkway and the pool are x+4 and 2x+4

the area of this rectangle minus the area of the pool is 196 square feet

(2x+4)(x+4)-(x)(2x)=196

2x^2+4x+8x+16-2x^2=196

combine similar terms

12x+16=196

12x=196-16

12x=180

x=180/12

x=15 feet is the width of the pool

check: 34*19-30*15=196

646-450=196

196=196

8 0

2 years ago

A rabbit population doubles every 4 weeks. There are currently five rabbits in a restricted area. If t represents the time, in w

My name is Ann [436]

First, you have to find how many weeks are in 98 and to do so, you would divide it by 7. which turns out to be 14. If you divide 14 by 4 you'll find that their population will double 3 times, but not 3.5 because it is every 4 full weeks.
The equation will look like this, however, I'm not completely certain about the format. I'm using the formula for exponential growth
P(t)=r(2)^t
I did use t as weeks, but for every 4 weeks. R is the number of rabbits. If we were to input our information, we'd get:
P(3)=5(2)^3
If you work it out, you get 40 rabbits. In 14 weeks, the rabbits will double 3 times, so if we were to just figure it out without using the formula, we could double 5 which is 10, double it again, which is 20, and then double it a third time. which is 40.

6 0

3 years ago

Determine which equation is parallel to the line JK and which is perpendicular to like JK

sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and $y = - \frac{1}{m}x + b$ will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ $n = - \frac{1}{m}$

Therefore, the equation of a straight line which is perpendicular to equation (1) will be $y = - \frac{1}{m}x + b$ where b is any real constant. (Answer)

3 0

3 years ago

Read 2 more answers

The angles in a triangle are such that one angle is 120 degrees more than the smallest angle, while the third angle is 3 times a

Westkost [7]

Answer:

a = 132; b = 12; c = 36

Step-by-step explanation:

a = b + 120

b = b

c = 3b

a + b + c = 180

(substitute these into the above equation)

b + 120 + b + 3b = 180

5b + 120 = 180

-120 -120

5b = 60

/5 /5

b = 12

(substitute b back into the first equations)

a = (12) + 120 = 132

b = (12)

c = 3(12) = 36

(check: 132 + 12 + 36 = 180)

7 0

3 years ago