Answer:
C. 42
Step-by-step explanation:
<em>Since the triangle making up the base of the right triangular pyramid is equilateral, the three lateral triangles will have equal areas. To find the surface area of the pyramid, find the area of one of the lateral triangles and multiply it by 3. Then, add that to the area of the triangle that forms the base.</em>
<em>Area of Lateral Triangle = 1/2 · base · height</em>
<em> = 1/2 · X · Z</em>
<em> = 1/2 · 4 units · 6 units</em>
<em> = 12 square units</em>
<em>Area of Base Triangle = 1/2 · base · height</em>
<em> = 1/2 · X · Y</em>
<em> = 1/2 · 4 units · 3 units</em>
<em> = 6 square units</em>
<em>Now, use the method described above to find the surface area of the pyramid.</em>
<em>Surface Area = 3( Area lateral ) + ( Area base )</em>
<em> = 3 ( 12 square units ) + ( 6 square units )</em>
<em> = 42 square units</em>
Answer:
Toby will reach more people in 40 phone calls
Answer:
S = (1 times 5)times 6
Step-by-step explanation:
Question 5. Because there are 6 friends and each of them gets 5. one of them gets 5 But there are 6 friends so you multiply by 6. 6 times 5 is 30
Answer:
(C) 2√15
Step-by-step explanation:
Recognize that all the triangles are right triangles, so are similar to each other. In these similar triangles, the ratio of the short side to the long side is the same for all.
... CB/CA = CT/CB
... CB² = CA·CT = 10·6 = 60 . . . . . . . . . . multiply by CA·CB; substitute values
... CB = √60 = 2√15 . . . . . . . take the square root; simplify
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<em>Comment on this solution</em>
The altitude to the hypotenuse of a right triangle (CB in this case) divides the hypotenuse into lengths such that the altitude is their geometric mean. That is ...
... CB = √(AC·CT) . . . . as above
This is true for any right triangle — another fact of geometry to put in your list of geometry facts.
<span> A. x²+2 - a polynomial
B.(x⁸-2)/(x⁻²+3) rational function
C. 7x⁷-2x⁻⁴+3 (It has negative value of exponent, so it cannot be a polynomial.)
D.x^x-1 (x is an exponent it cannot be a polynomial)</span>
