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cricket20 [7]
3 years ago
13

Given r(x) =11/(x-4)^2 which represents a domain restriction on r(x) and the corresponding inverse function?

Mathematics
2 answers:
saul85 [17]3 years ago
6 0

Answer:x>4;r-1(x)=4-(root of (11/x))

Step-by-step explanation:

Edgenuity 2020

xxTIMURxx [149]3 years ago
4 0

Given r(x) =11/(x-4)^2 which represents a domain restriction on r(x) and the corresponding inverse function?

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Anybody got an answer?
Anna11 [10]
For a regular n-agon with side length "s" and apothem "h", the area will be
.. A = n*(1/2)*s*h
Your area is
.. A = 10*(1/2)*(3.25 m)*(5 m) ≈ 81.3 m^2
8 0
3 years ago
Can I get some help on these please
torisob [31]
<h2>Ex 5</h2>

Simply multiply the equation by 6, in order to get rid of the denominators:

\dfrac{x}{2}+\dfrac{y}{3} = 4 \iff 3x+2y=24

<h2>Ex 6</h2>

We have to rearrange the equation in the form

(x-x_0)^2+(y-y_0)^2=r^2

So that r is the radius, and 2r will be the diamater. We have to complete the squares: rewrite the equation as

x^2-6x+y^2+8y=144

You can see that x^2-6x is the beginning of x^2-6x+9 = (x-3)^2

Similarly,  y^2+8y is the beginning of y^2+8y+16 = (y+4)^2

So, if we add 16 and 9 to both sides, the equation becomes

x^2-6x+9+y^2+8y+16=144+9+16 \iff (x-3)^2+(y+4)^2=169

So, now we know that r^2=169, and thus the radius is 13, so the diameter is 26.

3 0
4 years ago
A park ranger measures the heights in the box plot​​
lbvjy [14]

Answer:

The answer is c because 5 is not dotted anywhere?????

3 0
3 years ago
Help pleassssssssssssseeee
DiKsa [7]

Answer:

27in, 36in, 45in

Step-by-step explanation:

a = 27 \\ b = 36 \\ c = 45

{c}^{2} =  {a}^{2}  +  {b}^{2}

c = \sqrt{ {a}^{2} +  {b}^{2}  }

45{ = }^{?}   \sqrt{ {27}^{2} +  {36}^{2}  }

45  { = }^{?}   \sqrt{729 + 1296}

45  { = }^{?}   \sqrt{2025}

45 = 45

6 0
3 years ago
Please help me. I will give you brainliest!
Dvinal [7]

Answer:

50            6                   300

10               2                  20

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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