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2 years ago

Look at the proof. Name the postulate you would use to prove the two triangles are congruent.

Mathematics

1 answer:

vovikov84 [41]2 years ago

3 0

Answer:

Option A, SSS Postulate

Step-by-step explanation:

<em>Since it gives you three sides, that means that it is a SSS.</em>

There are no angles given which eliminates 2 options.

Answer: Option A, SSS Postulate

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Calculate a vector c in the same direction of the vector a and that has the same length as the vector b

Viktor [21]

For any scalar $t>0$ , $t\vec a$ is a vector pointing in the same direction as $a$ .

To force this vector to have the same length as another vector $\vec b$ , first normalize $t\vec a$ by dividing it by its norm,

$\dfrac{t\vec a}{\|t\vec a\|}=\dfrac{t\vec a}{t\|\vec a\|}=\dfrac{\vec a}{\|\vec a\|}$

then multiply this vector by the norm of $\vec b$ , so that

$\vec c=\dfrac{\|\vec b\|}{\|\vec a\|}\vec a$

To confirm that $\vec c$ has the same length as $\vec b$ :

$\|\vec c\|=\left\|\dfrac{\|\vec b\|}{\|\vec a\|}\vec a\right\|=\dfrac{\|\vec b\|}{\|\vec a\|}\|\vec a\|=\|\vec b\|$

8 0

3 years ago

Which best describes the complement of spinning any number less than 3?

tatuchka [14]

Answer:

<u>The complement of spinning any number less than 3, is spinning a number equal to or greater than 3.</u>

Explanation:

The complement of a subset is the subset of elements that are not in the given subset.

You must know which numbers the spinner has.

Assuming the spinner has the numbers 1, 2, 3, 4, the complement of spinning any number less than 3, is spinning a number that is not less than 3.

Then, that is spinning a number that is equal to or greater than 3.

The numbers that are equal to or greater than four, for a spinner that has the numbers 1, 2, 3, and 4 are 3 and 4.

Thus, the complement of spinning any number less than 3 is spinning a three or a four.

8 0

3 years ago

A total of 243 adults and children are at a movie theater. There are 109 more adults than children in the theater. If eh represe

Marina86 [1]

The system should look like this:

eh + b = 243
eh - b = 109

6 0

3 years ago

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

$104=1\times 2\times 2\times 2\times 13$

$88=1\times 2\times 2\times 2\times 11$

Form above , we can say that common factors are :

$HCF=2\times 2\times 2=8$

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0

3 years ago

Read 2 more answers

Mrs. Adenan sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the

stellarik [79]

63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent

63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent

7 0

3 years ago