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3 years ago

Which is a covalent compound?

2 answers:

soldier1979 [14.2K]3 years ago

5 0

Hey there. cOvalent bonds consisting sharing of electrons, generally between non-metals, in order to gain 8 electrons, each atom. As for metals, their bond is metallic and more a non-metal+metal, it is ionic, as the metal loses and th non-metal gains electrons. Methane, made up of two non-metals, hydrogen and Carbon are a typical example of a covalent bond. As carbon adds his 4 electrons to the 4 of Hydrogen, by octet rule, it ends up with 8 electrons around it. Hence, the answer is B. Hope you understood it.

alexira [117]3 years ago

4 0

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Classify the quadrilateral. parallel sides are indicated with arrows.

Sonbull [250]

A quadrilateral is a four-sided polygon that may be classified as: trapezoid, rectangle, square, rhombus, etc. This classification is based on the measurement of the four angles, the four sides, and their being parallel. Unfortunately though, I think you missed to include here the diagram that we are about to classify.

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3 years ago

A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction

alukav5142 [94]

The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.

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4 years ago

A spherical raindrop 2.7 mm in diameter falls through a vertical distance of 3950 m. take the cross-sectional area of a raindrop

Kazeer [188]

here we know that volume of the drop is given as

$V = \frac{4}{3}\pi R^3$

$V = \frac{4}{3}\pi (1.35\times 10^{-3})^3$

$V = 1.03 \times 10^{-8} m^3$

now the mass of the drop is given as

$m = \rho V$

$m = 1.03 \times 10^{-5} kg$

now the net buoyancy force on the drop is given as

$F_b = \rho_{air} V g$

$F_b = 1.2 (1.03\times 10^{-8})9.8$

$F_b = 1.21\times 10^{-7} N$

now the net force on the drop is

$F = F_g - F_b$

$F = 1.03\times 10^{-5}(9.8) - 1.21\times 10^{-7}$

now acceleration of the drop is given as

$a = \frac{F}{m}$

$a = 9.79 m/s^2$

now the speed of the drop is given as

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 0 = 2(9.79)(3950)$

$v_f = 278 m/s$

3 0

3 years ago

HELP ASAP THIS IS WORTH ALOT

coldgirl [10]

Answer:

An independent variable is the variable in an experiment that is changed. A dependent variable is the resulting variable that "depends" on the changes made to the independent variable. Controlled variables are all of the other variables that are kept the same between all changes made to the experiment. You would graph the independent variable and dependent variable. The independent variable will be found on the x-axis while the dependent variable can be found on the y-axis.

4 0

4 years ago

* if air is blown with a speed of 15 m/sec across the top of one side of a u-tube containing water, what will be the difference

guajiro [1.7K]

if air is blown with a speed of 15 m/sec across the top of one side of a u-tube containing water, the difference between the water levels on the two sides is 1.3 cm.

<h3>What is density?</h3>

The density is the ratio of the mass and volume of the particular object or liquid.

Applying the Bernoulli's equation across the ends of the tube A and B, we have

$P_{A} = P_{B} - \dfrac{1}{2} \rho Av^{2}$