We don't see any circuit diagrams.
This worries us for a few seconds, until we realize that we don't know anything about the experiment described in the problem either, so we don't have to worry about it at all.
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Answer:
The Resultant Induced Emf in coil is 4∈.
Explanation:
Given that,
A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.
To find :-
find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).
So,
Emf induced in the coil represented by formula
∈ =
...................(1)
Where:
.
{ B is magnetic field }
{A is cross-sectional area}
.
No. of turns in coil.
.
Rate change of induced Emf.
Here,
Considering the case :-
&
Putting these value in the equation (1) and finding the new emf induced (∈1)
∈1 =
∈1 =
∈1 =![4 [-N\times\frac{d\phi}{dt}]](https://tex.z-dn.net/?f=4%20%5B-N%5Ctimes%5Cfrac%7Bd%5Cphi%7D%7Bdt%7D%5D)
∈1 = 4∈ ...............{from Equation (1)}
Hence,
The Resultant Induced Emf in coil is 4∈.
Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;

where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N

186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²