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alexdok [17]
3 years ago
14

I need to graph these two problems

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

I graphed it in the pic below

Step-by-step explanation:

The first one is in green and the second in red

+4 and +6 is where the line intercepts the y axis

-4x and -2x are the slopes.

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(05.05)Polygon ABCD has the following vertices:
Kaylis [27]

Answer is option b)38.5 sq.units

Given vertices are A(-4,2) ,B(3,2),C(3,-5) and D(-4,-2)

Area of polygon is defined in the image.

If you have any doubts see the image or ask in comments box.

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

4 0
3 years ago
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
Cheryl bought 16 pounds of apples for $12. How much did it cost per
algol [13]

Answer:

.75

Step-by-step explanation:

$12 / 16 = $0.75

8 0
3 years ago
Read 2 more answers
1 card holds 10 stickers, 59 stickers. How many cards are needed
pochemuha
The answer is

6 cards
6 0
3 years ago
How do you solve x-y=1 ; x+y=3. Please Explain
KIM [24]
You isolate one variable. Let's say that x will be that variable in the first equation:
x-y=1
 +y  +y
x=y+1
So now you have the equation for x.  All you have to do is substitute it into the other:
x=y+1
(y+1)+y=3
Combine like terms and solve:
2y+1=3
    -1  -1
2y=2
2y/2=2/2
y=1
Now that you have the value of one, substitute it into either of the equations to find x.
If you put it in the first:
x-1=1
 +1  +1
x=2
If you put it into the other, you would get the same answer.
Therefore, y=1 and x=2
8 0
3 years ago
Read 2 more answers
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