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Pani-rosa [81]
3 years ago
13

How many 2/5 pound servings are in a 1/4 of a bag of candy?

Mathematics
1 answer:
inessss [21]3 years ago
8 0
Your amswer is 5/9 hope this helps
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Mr. Jackson sold 3 computer monitors in the first year. In the second year, he sold 4 times as many monitors as in the first yea
GenaCL600 [577]

Answer:

There wasn't really a question here but for both the answers is

for year 2 we got 12 sales

for year 3 we got 18 sales

Step-by-step explanation:

since the first year Mr.Jackson sold 3 computer monitors then in the second year he must've multiplied the times he had sold it which means 4 x 3 which equals 12

as well as the third year, on the third year he sold 6 times the first year so it means 6 x 3 which equals 18

8 0
3 years ago
Read 2 more answers
Multiply 11x +3 by 4. What is the<br> product?
faltersainse [42]

(11x+3)4

it will be 44x +12

4 0
3 years ago
Help?. . What is the equation of the function y=5/x translated 4 units to the left and 3 units up?. . I don't even know where to
Dahasolnce [82]
Y = 5/x
If you want to shift the function 4 units left, you can add 4 to the x-value in the parent function:
y = 5 / ( x + 4 )
After that, you can add 3 to your function to shift it up 3 units.
y = 5 /( x + 4 )  + 3 ( the final equation )
4 0
3 years ago
Please solve this ASAP!!! :)
kherson [118]

Answer:

1). Area = 37 cm²

2). Area = 120 cm²

Step-by-step explanation:

Figures in the picture attached are the examples of composite figures.

1). Area of the composite figure = Area of rectangle A + Area of rectangle B

   Since area of rectangle = Length × width

   Area of rectangle A = 8 × 2 = 16 cm²

   Area of rectangle B = 3 × 7 = 21 cm²

   Area of the composite figure = 16 + 21 = 37 cm²

2). Area of the composite figure = Area of C + Area of D

                                                     = (3×4) + (9×12)

                                                     = 12 + 108

                                                     = 120 cm²

4 0
3 years ago
CosA + cosB - cosC = -1 + 4cosA/2 cosB/2 sinC/2
Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

(cos A+ cos B)-cos C

=2cos \frac{A+B}{2}cos \frac{A-B}{2}-cos C~~~...(1)\\A+B+C=180\\A+B=180-C\\\frac{A+B}{2}=90-\frac{C}{2}\\cos \frac{A+B}{2}=cos(90-\frac{C}{2})=sin \frac{C}{2}\\cos C=1-2sin^2\frac{C}{2}\\(1)=2 sin \frac{C}{2} cos \frac{A-B}{2}-1+2sin^2\frac{C}2}\\=2sin\frac{C}{2}[cos \frac{A-B}{2}+sin \frac{C}{2}]-1~~~...(2)\\\\now~again~A+B+C=180\\C=180-(A+B)\\sin\frac{C}{2}=sin(90-\frac{A+B}{2})=cos \frac{A+B}{2}\\(2)=2sin\frac {C}{2}[cos \frac{A-B}{2}+cos \frac{A+B}{2}]-1\\

=-1+2sin\frac{C}{2}*2cos \frac{\frac{A-B}{2} +\frac{A+B}{2} }{2} cos \frac{\frac{A-B}{2} -\frac{A+B}{2} }{2} \\=-1+4sin\frac{C}{2} cos \frac{A}{2} cos\frac{-B}{2} \\=-1+4 cos \frac{A}{2} cos \frac{B}{2} sin \frac{C}{2}\\(cos(-B)=cos B)

8 0
4 years ago
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