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FrozenT [24]
3 years ago
9

On Monday at the county fair , Jared played a game and won 75 tickets . On Tuesday , he won 105 tickets on Wednesday , he won 12

7 tickets , but the spent 250 of them on a prize . How many more tickets does Jared need to win a prize that costs 150 tickets ?
Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0

Answer: 93

Step-by-step explanation:

75+105+127= 307

307-250= 57

150-57= 93 (57 + 93 = 150)

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y  , 8 z>

Δf = λ Δh

So

< 8 ,8 , 4> = < 8  λ x ,8 λ y  , 8 λ z>

8 = 8  λ x                     -------------1

8 = 8 λ y                      ----  ------2

4 = 8 λ z                    ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36

So the value of λ is

\lambda =\pm \dfrac{1}{2}

When λ = 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0
3 years ago
Read 2 more answers
Solve <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%20%3D%20%20%5Cfrac%7Bh%7D%7Bh%20-%203000%7D%20" id="TexFormula1" ti
dezoksy [38]
<span>\sqrt{3}(h-3000)=h
</span>(\sqrt{3}h-\sqrt{3}(3000)=h
(\sqrt{3}-1)h=\sqrt{3}(3000)
h=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}
=\frac{\sqrt{3}(3000)}{(\sqrt{3}-1)}
=7098.076 (approximately)
8 0
3 years ago
A toll collector on a highway receives ​$8 for trucks and ​$5 for sedans. At the end of a 3​-hour ​period, she collected ​$208.
Vilka [71]

Answer:

The number of trucks and sedans can be

(0 trucks ,26 sedans)

(8 trucks ,21 sedans)

(24 trucks ,11 sedans)

(25 trucks ,1 sedans)

(32 trucks ,6 sedans)

(16 trucks ,16 sedans)

Step-by-step explanation:

Given:

The  cost for trucks =$5

The cost for sedans  =$8

The total amount collected = $208

To Find:

Number of trucks and sedans passed through the toll booth =?

Solution:

Let the number of trucks be x and the number of sedans be y

Then

5x + 8y = 208-------------------------------(1)

By Trail and error method

5(0) + 8(26) = 208

5(8) + 8(21) = 208

5(24) +8(11) =208

5(25) + 8(1) = 208

5(32) + 8(6) =208

5(16) + 8(16) = 208

8 0
3 years ago
I need help with 8-11....
MaRussiya [10]
8. Quadrants
9. Proportion
10. Proportionality
11. Dimensional analysis
8 0
3 years ago
Can someone pls help me find what is 1/10+12/20?
irga5000 [103]

Answer:

\frac{7}{10}

Step-by-step explanation:

\frac{1}{10} can also be written as \frac{2}{20}

\frac{2}{20} +\frac{12}{20} =\frac{14}{20}

Simply to \frac{7}{10}

-OTHER METHOD-

\frac{12}{20} can be simplified to \frac{6}{10}

\frac{1}{10} +\frac{6}{10} =\frac{7}{10}

7 0
3 years ago
Read 2 more answers
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