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2 years ago

8

The Suarez family paid 15.75 for 3 movie tickets. How much money would they paid for 12 tickets

2 answers:

s344n2d4d5 [400]2 years ago

8 0

The asnwer is $63.

Hope that hlpes!!!

seraphim [82]2 years ago

6 0

63 is the answer because 15.75÷3=6.25 and 6.25×12 is 63

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Probability of Rolling a 5 on a 6 sided die

andre [41]

Answer:

1/6

Step-by-step explanation:

Since there are 6 sides, rolling 1 of the numbers on the die will be a 1 out of 6 chance.

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2 years ago

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Scoring a hole-in-one is the greatest shot a golfer can make. Once 5 professional golfers each made holes-in-one on the 7th hole

adell [148]

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3 years ago

Using coupons you spell $91 grocery shopping this is 65% of the total retail price of groceries how much would you have spent if

Andrews [41]

$140 because

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2 years ago

What is 30 percent of 25

sweet [91]

7.5 is 30 percent of 25 because

25 divided by 10 is 2.5 times 3 is 7.5

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2 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

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2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

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$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago