I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
Step-by-step explanation:
1104 = 2⁴×3×23
48 = 2⁴×3
1104 ÷ 48 = 23
Answer:
a = 30
b = 40
C
Step-by-step explanation:
This requires that you use a proportion.
a / (a + 15) = 40 / 60
The small triangle's sides are in proportion to the large triangles sides.
Reduce the right. Divide top and bottom by 20
a/(a + 15) = 40/20 // 60/20
a/(a + 15) = 2/3
Cross multiply
3a = 2(a + 15) Remove the brackets on the right.
3a = 2a + 30
Subtract 2a from both sides
3a-2a = 30
a = 30
Find B
b is done exactly the same way.
b/(b+20) = 2/3
3b = 2b + 40
3b - 2b = 40
b = 40
Let
x--------> the amount of gummy candy in pounds
y--------> the amount of jelly beans in pounds
z--------> the amount of hard candy in pounds
we know that
--------> equation 
--------> equation 
--------> equation 
Substitute equation in equation and equation
![[2y]+y+z=9](https://tex.z-dn.net/?f=%5B2y%5D%2By%2Bz%3D9)
-----> 
------> equation 
![2[2y]+3y+3z=23](https://tex.z-dn.net/?f=2%5B2y%5D%2B3y%2B3z%3D23)
-----> 
------> equation 
using a graphing tool ------> Solve the system of equations
see the attached figure
the solution is the point 
<u>Find the value of x</u>
therefore
<u>the answer is</u>
the amount of gummy candy is 
the amount of jelly beans is 
the amount of hard candy is 
