Ask question

Ask question

All categories

3 years ago

14

Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively. Which statement is true about lines a and

b?

2 answers:

Tpy6a [65]3 years ago

4 0

Answer:

C. I just took the test

blondinia [14]3 years ago

3 0

You haven't included a picture of the diagram or the statements!

You might be interested in

Divide (- 6 + i)/(1 - 2i) =

Kaylis [27]

$~~~\dfrac{(-6 +i)}{(1- 2i)}\\\\\\=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{-6-12i+i+2i^2}{1-(2i)^2}\\\\\\=\dfrac{-6-11i-2}{1+4}~~~~~~~~~~~~~;[i^2=-1]\\\\\\=\dfrac{-8-11i}{5}\\\\\\=-\dfrac 85-\dfrac{11}{5}i$

4 0

1 year ago

Read 2 more answers

Write an equation for the direct variation (y varies directly with x) if y=12 when x=4.

Olegator [25]

Hdhssuejzzsxfffdfggfds

6 0

3 years ago

HELPPP look at the figure.<br> What is the slope of the graph?

m_a_m_a [10]

Answer:

-5

Step-by-step explanation:

becuses look at where the slope intersecs the y axis. Its -5

EZ

3 0

3 years ago

Read 2 more answers

What monomial multiplied by - 3x ^ 3 * y equals 18x ^ 9 * y ^ 4 Explain how you were able to determine the coefficient and the e

Archy [21]

Answer:

-6x^6y^5

Step-by-step explanation:

you have to find p such that

(-3 $x^{3}$ y)(p) = 18 $x^{9}y^{4}$

So just divide to find p

p = $\frac{18x^{9}y^{4} }{-3x^{3}y}$ = -6 $x^{6}y^{5}$

7 0

2 years ago

vodka [1.7K]

So I = Prt

I for interest charge
P for principal ($4,840)
r for rate (6%)
t for time (2 yrs)

So you would then plug the information into the equation.....

I = 4,840*.06*2
I = 580.80

So the answer to your question is $580.80 which is option B

Hope this helps! :)

6 0

3 years ago