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3 years ago

Como divido 2 5/8 / 5 ayuda

Mathematics

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

21/40

Step-by-step explanation:

2 5/8 / 5 =

= 2 5/8 / 5/1

= 21/8 × 1/5

= 21/40

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Given parallelogram EFGH, where EF = 5x + 18, HE = 3x + 4 and the perimeter is 60, which value of GH

skelet666 [1.2K]

Given the perimeter of the parallelogram in the image below is 60, the value of GH will be: 23.

Recall:

Perimeter of a parallelogram = 2(a + b), where a is the side length and b is the base length.
Opposite sides of a parallelogram are equal.

Given the parallelogram as shown in the diagram below, where:

base (b) = EF = 5x + 18

side (a) = HE = 3x + 4

Perimeter = 60

Plug in the values into the formula:

60 = 2[(3x + 4) + (5x + 18)]

60 = 2[3x + 4 + 5x + 18]

60 = 2[8x + 22]

60 = 16x + 44

60 - 44 = 16x

16 = 16x

1 = x

x = 1

GH = EF = 5x + 18 (equal opposite sides of parallelogram)

GH = 5x + 18

Plug in the value of x

GH = 5(1) + 18

GH = 23

Learn more about the perimeter of a parallelogram on:

brainly.com/question/884700

6 0

3 years ago

Write three ratios equivalent to the given ratio.include the simplest form if not given.circle the simplest form.10/12

kobusy [5.1K]

The simplest form is 5/6, an equivalent ratio is 20/24 and another is 30/36

7 0

3 years ago

A 20-volt electromotive force is applied to an LR-series circuit in which the inductance is 0.1 henry and the resistance is 30 o

Dafna1 [17]

Answer:

$i(t)=(2/3)(1-e^{-300t})$

Step-by-step explanation:

Before we even begin it would be very helpful to draw out a simple layout of the circuit. Then we go ahead and apply kirchoffs second law(sum of voltages around a loop must be zero) on the circuit and we obtain the following differential equation,

$-V +Ldi/dt+Ri=0$

where V is the electromotive force applied to the LR series circuit, Ldi/dt is the voltage drop across the inductor and Ri is the voltage drop across the resistor. we can re write the equation as,

$di/dt+Ri/L=V/L$

Then we first solve for the homogeneous part given by,

$di/dt+Ri/L=0$

we obtain,

$i(t)_{h} =I_{max}e^{-Rt/L}$

This is only the solution to the homogeneous part, The final solution would be given by,

$i(t)=i(t)_{h} +c$

where c is some constant, we added this because the right side of the primary differential equation has a constant term given by V/R. We put this in the main differential equation and obtain the value of c as c=V/R by comparing the constants on both sides.if we put in our initial condition of i(0)=0, we obtain $I_{max} =V/R$ , so the overall equation becomes,