Como divido 2 5/8 / 5 ayuda

Please Help!! George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value fo

luda_lava [24]

For the answer to the question above, I'll provide a solution to my answer below.
(4 / 5) + (3 / x) = (1/2)

x cannot equal 0 

(4x + 15) / 5x = 1/2 
2(4x + 15) = 5x 
8x + 30 = 5x 
3x = -30 
x = -10
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

5 0

3 years ago

Read 2 more answers

Julio bought tables and chairs for his restaurant. He bought 16 total items and spent $1800. Each table cost $150 and each chair

uysha [10]

Answer:

He bought 6 chairs and 10 tables.

Step-by-step explanation:

x+y = 16

he spent = $1800

1 chair = $50

y chairs = $50y

1 table = $150

x chairs = $150x

so, 150x+50y = 1800

we got two equations :

x+ y = 16

150x+50y = 1800

Using. substitution method,

x+y = 16

so, x = 16-y

Now

150x+50y =1800

or, 150(16-y) + 50y = 1800

or, 2400-150y+50y = 1800

or, 2400-1800 = 150y-50y

or, 600=100y

so, y = 6

now,

x+y = 16

or, x + 6 = 16

so, x = 10

4 0

2 years ago

Every week, Judy goes to the supermarket and buys the following: $5$ carrots at $\$1$ each, $3$ bottles of milk at $\$3$ each, $

Flauer [41]

Answer:

She spends $30 in total.

Step-by-step explanation:

Suppose that you buy X units of a given product with a price Y, then the total cost here is X*Y, with this we can solve our problem:

Every week Judy buys:

5 carrots, at $1 each, so she spends 5*$1 = $5 in carrots.

3 bottles of milk at $3, so she spends 3*$3 = $9 in milk bottles.

2 pineapples at $4 each (but the pineapples are at half price, so this week the pineapples cost $4/2 = $2), so she spends 2*$2 = $4 in pineapples.

2 bags of flour at $5 each, so she spends 2*$5 = $10 in flour.

1 giant container of ice cream, she spends $7 on it.

So the total money that she speends is:

$5 + $9 + $4 + $10 + $7 = $35

And she has a coupon for $5 in any order equal to or larger than $25, his order is larger than $25, so she can use the coupon.

So she will spend a total of $35 - $5 = $30

She spends $30 in total.

3 0

3 years ago

Alcona has a radius of 5 inches and a height of 5 inches what is the volume up and come to the nearest 10 inch cube :-)

Nookie1986 [14]

Pi * 5 squared = 25 Pi
25 Pi * 5 = 125 Pi or 392.6990817
and I'm not sure how to round to inch cube sorry. :(

4 0

3 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

7 0

2 years ago