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Vedmedyk [2.9K]
3 years ago
9

Alana needs 4.62 m of fabric to make curtains. The fabric is sold in tenths of a metre. How much fabric should she buy

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

fabric is usually better with a 3" hem to "weight" the hem and help it hang properly. To find the amount you need for the set of curtains: Total LENGTH needed for each panel X (times) the NUMBER of panels / (divided by) 36" (for a yard of fabric or 39.37" for a meter of fabric) = TOTAL.Step-by-step explanation:

hope it help

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mary purchased 3 1/2 pounds of bananas. If the loaf of banana bread requires 3/4 pounds of bananas, how many loaves of banana br
nikklg [1K]
For this one a simple way that you can think of it is that 1 pound of banana is equivalent to 100, 3/4 pounds of banana is 75, 1/2 pounds of banana is 50, etc. 

3 1/2 pounds of banana = 350 

3/4 pounds of banana = 75 

If i want to find out how many loafs of banana bread I can make if ONE loaf requires 3/4 pounds of banana, and i have 3 1/2 pounds of banana then I divide:

350 / 75 = 4.66 

So, with 3 1/2 pounds of bananas you can successfully create 4 loafs of banana bread. the remaining .66 is not enough banana to make another loaf. 
8 0
3 years ago
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One-third of 2c subtracted frome 5 times nine
lilavasa [31]
-44.8 is the answer.
4 0
3 years ago
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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
_-16(3)^2 = 80(3) +0 =0
Varvara68 [4.7K]

Answer:

55

Step-by-step explana

black lives matter

3 0
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