You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
Multiply row 2 by -1 and add it to row 3
_____
It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.
You can switch columns, but that doesn't get you any closer to a solution here.
If I were trying to find a solution, I might
switch rows 1 and 2
multiply the new row 1 by -3 and add it to the new row 2
multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
Answer:
15x^2y^2+9x^2y+2xy^2+27xy
Step-by-step explanation:
Answer:
The two lines are not perpendicular because the product of their slopes is not equal to -1
Step-by-step explanation:
The product of the slopes of the perpendicular line is -1
- That means one of them is and additive and multiplicative inverse of the other
- If the slope of one of them is m, then reciprocal m and change its sign, then the slope of the perpendicular is
- The formula of the slope is

Let us find from the graph two points lie on each line and calculate the slopes of them and then find its product if the product is -1, then the two lines are perpendicular
From the graph
∵ The red line passes through points (4 , 0) and (0 , 8)
∴
= 4 and
= 0
∴
= 0 and
= 8
∵ 
∴ The slope of the red line is -2
∵ The blue line passes through points (5 , 5) and (0 , -5)
∴
= 5 and
= 0
∴
= 5 and
= -5
∵ 
∴ The slope of the blue line is 2
∵ The products of the slopes of the two lines = -2 × 2 = -4
∴ The product of the slopes of the lines not equal -1
∴ The two lines are not perpendicular
Hello,
The area of the circle=
πr^2
or A=πr^2
1976=πr^2
Divided π or 3.14 from both side
1976/3.14=πr^2/π
629.3≈r^2
Square root from both side to get
r≈25.1 inches
d=2r
d=2(25.1)
d≈50.2 inches
C=πd
C=50.2π or C≈157.628 inches. Hope it help!