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Gala2k [10]
3 years ago
5

Find the pattern and use inductive reasoning to predict the next number in the sequence 5,5,10,30,120,…

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
600 because it’s times 5
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In simplest radical form, what are the solutions to the quadratic equation 6 = x2 - 10x?
WARRIOR [948]

Answer:

x = 5 - \sqrt{31}, 5 + \sqrt{31}

Step-by-step explanation:

6 = x^2 - 10x

0 = x^2 - 10x - 6

Let's use the quadratic formula. ( x = \frac{-b +- \sqrt{b^2 - 4ac}}{2a})

x = \frac{10 +- \sqrt{-10^2 - 4(-6)}}{2}

x = \frac{10 +- 2\sqrt{31} }{2}

  = 5 +- \sqrt{31}

x = 5 - \sqrt{31}, 5 + \sqrt{31}

5 0
4 years ago
David is saving money to buy a game. So far he has saved $30, which is one-third of the total cost of the game. How much does th
vodka [1.7K]
1/3=30
2/3=60
3/3=90
The game costs $90
8 0
3 years ago
Read 2 more answers
A recipe for cookies needs 240g of flour to make enough cookies for 5 people. How much flour would you need to make cookies for
Serga [27]

Answer:

720g

Step-by-step explanation:

5 people = 240g

×3 x3

15 people = 720g

5 0
3 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
the number of members in a club dropped from 80 to 52. what is the percent of decrease in the number of members
Illusion [34]
Percent of decrease :
Original - New / Original
so...
80 - 52 / 80 ---->
28/80
.35 multiply by 100 to get percent
35% increase Hope I helped if you have any questions let me know! :)



7 0
3 years ago
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