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andreyandreev [35.5K]
3 years ago
8

Second post. third is coming up

Mathematics
1 answer:
Alja [10]3 years ago
5 0
Sorry, but the paper is too blurry fam
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What is the point slope form of the line with slope −14 that passes through the point (−2, 9)?
Mice21 [21]

Answer:

y - 9 = -14 (x + 2)

Step-by-step explanation:

Point-slope form --> y - y1 = m ( x - x1)

slope = -14

y1 = 9

x1 = -2

Let's put the values all together:

y - 9 = -14 (x - - 2)

y - 9 = -14 (x + 2) ---> final answer

6 0
3 years ago
Read 2 more answers
Determine the value of z in the figure answers: z = 50° z = 45° z = 10° z = 30°
ycow [4]

Answer:

z = 10°

Step-by-step explanation:

Since the two sides are equal, the two base angles have to be equal

That means that 5z and 130 form a straight line and add to 180 degrees

5z+130 = 180

Subtract 130 from each side

5z = 50

Divide by 5

5z/5 = 50/5

z=10

3 0
3 years ago
75 percent of a number is 354. find the number
slavikrds [6]

Answer: 75% of 472 is 354

Step-by-step explanation: you can figure this out by dividing 354 by 3 = 118, then you multiply that 118 by 4 = 472.

7 0
3 years ago
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A fitness club offers two membership plans.
iogann1982 [59]
A i think hope this help
4 0
3 years ago
There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
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