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mezya [45]
3 years ago
14

It cost $200 to rent a room at an event center. The event center charges an additional $13 per person for food. Write an algebra

ic expression for the total cost of an event for n people
Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:13n=200

Step-by-step explanation$13 for pood per person. n is the number of people. 13 times n equals 200

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If the sudent has grades of 62,67,75, and 89 what is the student's grade befire taking the final exam?
MrMuchimi

Answer:

73.25

Step-by-step explanation:

Add all numbers and divide by 4 to get the average grade.

3 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Hank is throwing a surprise party. The party costs $20 per person. Create an equation and graph to represent the relationship be
o-na [289]

Answer:

10 people,200 dollars. 20 people,400 dollars.100 people,2000 dollars.300 people,6000 dollars.

6 0
3 years ago
If a line with a slope of -2 crosses the y-axis at (0,3) what is the equation of the line
Ghella [55]
Hello!

The equation can be written as seen below. You only need a y-intercept and slope to write the equation.

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I hope this helps!
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What is the value of x
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Answer:

x = 2

Step-by-step explanation:

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3 years ago
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