by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Can you write the full question
Answer:
4p^3 (4p + 1)
Step-by-step explanation:
All we can do with this equation is factor it.
16p^4 + 4p^3
When we look at the coefficients, there is a common factor of 4 with 16 and 4. The p's are also common factors, and we can take out a common factor of x^3. We can combine these common factors and take them out of the equation at the same time.
4p^3 (4p + 1)
V=hpir^2
tricky, they didn't give us radius
they just gave circiufmerece
c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r
subsitutet
v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches
Answer:
Simple, Her Pentagon is not straight
Step-by-step explanation:
Carla's Pentagon is not straight. Her symmetry line is off scale. Simply fix the Line on the pentagon And it will be correct.
Hope this helps ^
