Answer:
the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331
Step-by-step explanation:
Given that:
Mean = 30000
Standard deviation = 9000
sample size = 100
The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:





From Z tables:


Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331
Answer:
Solve:
(x=44, y=21} I think
Step-by-step explanation:
Answer:Mark Is 9 years old; Christine is 5 years old
Step-by-step explanation:
Present age
LET mark age be x
Christine be x-4 yrs
In 3 yrs Time
Mark will be x+3 yrs old
Christine will be (x -4 +3) = x-1 years old
Also, In 3 years time
Christine = 2/3 Mark
such that
x-1 = 2/3(x+3)
x -1= 2x+6 / 3
3x -3= 2x+6
3X--2X = 6+3
=X=9
Mark Is 9 years old
Christine is x -4 = 9-4=5 years old
The answer is 2... I think idrk 2 second ago was I thinking abt Damon Salvatore bunt GOOD LUCK!!!
Answer:
490/10=49
Every 10 numbers is one number. I divided by 490 because it says less then 500
Step-by-step explanation: