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o-na [289]
3 years ago
6

Suppose an x-y axis is superimposed on the map with its origin at Des Moines, Iowa. also suppose a cold front is passing through

the US at noon having shaped roughly like a parabola with its vertex at Des Moines, Iowa ad a vertical stretch/ shrink factor of 1/20 if the independent varaible is measured in hundreds of miles. What type of function are you working with. How do you know? Is the leading coefficient positive or negative? how do you know?

Mathematics
1 answer:
V125BC [204]3 years ago
5 0
Based on the figure and the problem, the cold front is in the shape of a parabola. Therefore, the function is of second degree or a quadratic function. Since the graph of the parabola is curved upwards and its degree is 2 which is even, the leading coefficient is positive.
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Step-by-step explanation:

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Step-by-step explanation:

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Which relation is a function?
Brums [2.3K]
The second relation is a function.

For a relation to be a function, each x-value can only have a singular corresponding y-value. Since all other relations feature x-values with multiple y-values, the second relation is a function.
5 0
3 years ago
A new car is purchased for 24600 dollars. The value of the car depreciates at 13.75% per year. What will the value of the car be
liraira [26]

Answer:

The value will be $1,411.20

Step-by-step explanation:

What we do here is to set up an exponential equation to calculate the value.

Mathematically it will look like this;

V = I(1-r)^n

where V is the future value

I is the initial amount = 24,600

r is rate of decrease = 13.75% = 13.75/100 = 0.1375

n is the number of years = 15 years

substituting these values, we have

V = 24,600(1-0.1375)^15

V = 24600(0.8625)^15

V = 1,411.165582454129

= $1,411.20

7 0
3 years ago
A closed cylindrical can of fixed volume V has radius r.a) Find the surface area, S, as a function of r.b) What happens to the v
andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if  V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = \frac{10}{\pi r^{2}}

By placing the value of h in the formula of surface area,

S = 2\pi r(r+\frac{10}{\pi r^{2}})

Now we can get the points to plot the graph,

r       -2             -1         0       1            2

S    -13.72     -13.72     0    26.28    35.13

7 0
4 years ago
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