Anyone willing to help me out. I will brainliest the first answer I see

seropon [69]

Answer:

2x = y

Step-by-step explanation:

As you can see in the table, y = 2x, this is proven by the fact that if you divide any value in the y of the table by 2 you will get its corresponding x value, proving that 2x = y is the function that is used to represent this table's value.

8 0

2 years ago

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At Max's restaurant the cost of a child's dinner is $3.00 less than the cost of an adult dinner. You bought four children's dinn

iris [78.8K]

The answer is that the adult price was 6 dollars

3 0

3 years ago

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Luis set up an A-frame ladder so that the angle formed between each side of the ladder and the ground is 125 degrees. What is th

Firlakuza [10]

Answer:

70°

found by considering A-frame ladder as a triangle

Step-by-step explanation:

Given that,

angle form on either side of A-frame ladder with the ground = 125°(exterior)

As it is a A-frame ladder so its a triangle, we will find the angle at the top of ladder by using different properties of triangle

1) find interior angle form by A-frame ladder with the ground

125 + x = 180 sum of angles on a straight line

x = 180 - 125

x = 55°

2) find the angle on top of ladder

55 + 55 + y = 180 sum of angle of a triangle

110 + y = 180

y = 180 - 110

y = 70°

3 0

3 years ago

An 8-foot by 5-foot section of wall is to be covered by square tiles that measure 4 inches on each side. If the tiles are not cu

ExtremeBDS [4]

Answer:

30 tiles

Step-by-step explanation:

SO we need to find the area of the wall so we do

8 feet * 5 feet = 40 feet squared

then we find that area in inches

40*12=480

Now we find the area of the tiles

4*4=16

So now we divide to find how many tiles are needed

480/16=30

Our answer is 30

6 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago