Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3
A. 8 x 10^ -4
D. 3 x 10^ -2
Answer:
The dimensions of the bar are width = 4.68099 feet and length = 10.06198 feet
Step-by-step explanation:
A chocolate bar has a rectangular shape, therefore it's area is given by the following formula:
area = width*length
In this case the length is 0.7 feet longer than twice the width, therefore:
length = 2*width + 0.7
Applying the second equation on the first one and using the data from the question we have:
47.1 = width*(2*width + 0.7)
47.1 = 2*width² + 0.7*width
2*width² + 0.7*width = 47.1
width² + 0.35*width = 23.55
width = 
width = 4.68099 or width = -5.03099
Since the width can't be negative, it can only be 4.68099 feet.
length = 2*4.68099 + 0.7 = 10.06198 feet.
y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b