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3 years ago

Please solve: 8n+2≤8n−9! Show your work please!

1 answer:

4 0

This doesn’t make any sense, because 8n-8n<=-9-2
Which means 0<=-11 which doesn’t make sense, therefore this there are no solutions for this inequality.

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maurice has 54 fewer comic books than rebecca.they have 130 comic books together .How many comic books are in maurices collectio

eduard

Answer

Rebecca has 76 comic books
Maurice has 54 comic books

Step-by-step

Since there are 54 fewer comics and together they have 130 comics, you should subtract 54 from 130. Once you do that your answer will be 76; and that is how many comics Rebecca has. And 76+54=130 so Maurice has 54 comics

3 0

3 years ago

Hello,can you answer this question asap thxs

Ivan

9514 1404 393

Answer:

111 1/9 pounds

Step-by-step explanation:

The given relationship is ...

delivered = ground × (1 -10%)

Then ...

ground = delivered/0.90 = 100 lb/0.90 = 111 1/9 lb

It is necessary to grind 111 1/9 pounds of grain to have exactly 100 lb after a 10% payment.

5 0

2 years ago

Ollie drank 3/4

natita [175]

There are 4 ounces left because 1/4 is 4 and 3/4 would be 12. 16-12 = 4

4 0

3 years ago

Read 2 more answers

Using the standard 28/36 ratio, determine the maximum allowable recurring debt for someone with a

Mumz [18]

The maximum allowable recurring debt for someone with a monthly income of $54.875 is $4.39.

<h3 /><h3>Maximum allowable recurring debt:</h3>

Using this formula

Maximum allowable recurring debt=Ratio×Monthly income

Where:

Ratio=28/36

Monthly income=$54.875

Let plug in the formula

Maximum allowable recurring debt=(36%×$54.875)-(28%×$54.875)

Maximum allowable recurring debt=$19.755-$15.365

Maximum allowable recurring debt=$4.39

Inconclusion the maximum allowable recurring debt for someone with a monthly income of $54.875 is $4.39.

Learn more about maximum allowable recurring debt here:brainly.com/question/5083803

4 0

2 years ago

Two solutions to y'' – 2y' – 35y = 0 are yı = e, Y2 = e -5t a) Find the Wronskian. W = 0 Preview b) Find the solution satisfying

pashok25 [27]

Answer:

a. $w(t)=-12e^{2t}$

b. $y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}$

Step-by-step explanation:

We have a differential equation

y''-2 y'-35 y=0

Auxillary equation

$(D^2-2D-35)=0$

By factorization method we are finding the solution

$D^2-7D+5D-35=0$

$(D-7)(D+5)=0$

Substitute each factor equal to zero

D-7=0 and D+5=0

D=7 and D=-5

Therefore ,

General solution is

$y(x)=C_1e^{7t}+C_2e^{-5t}$

Let $y_1=e^{7t} \;and \;y_2=e^{-5t}$

We have to find Wronskian

$w(t)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

Substitute values then we get

$w(t)=\begin{vmatrix}e^{7t}&e^{-5t}\\7e^{7t}&-5e^{-5t}\end{vmatrix}$

$w(t)=-5e^{7t}\cdot e^{-5t}-7e^{7t}\cdot e^{-5t}=-5e^{7t-5t}-7e^[7t-5t}$

$w(t)=-5e^{2t}-7e^{2t}=-12e^{2t}$

a. $w(t)=-12e^{2t}$

We are given that y(0)=-7 and y'(0)=23

Substitute the value in general solution the we get

$y(0)=C_1+C_2$

$C_1+C_2=-7$ ....(equation I)

$y'(t)=7C_1e^{7t}-5C_2e^{-5t}$

$y'(0)=7C_1-5C_2$

$7C_1-5C_2=23$ ......(equation II)

Equation I is multiply by 5 then we subtract equation II from equation I

Using elimination method we eliminate $C_1$

Then we get $C_2=-\frac{5}{2}$

Substitute the value of $C_2$ in I equation then we get

$C_1-\frac{5}{2}=-7$

$C_1=-7+\frac{5}{2}=\frac{-14+5}{2}=-\frac{9}{2}$

Hence, the general solution is

b. $y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}$

7 0

3 years ago