Question

X² +10x+3=0how do I slove it with the quadratic formula?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The equation is already in standard form [ ax² + bx + c = y ] so we can find the values of each variable.

a = 1

b = 10

c = 3

y = 0

Quadratic formula: $x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

Solve using the formula:

$x=\frac{-10+-\sqrt{10^2-4(1)(3)} }{2(1)}$

$x=\frac{-10+-\sqrt{100 - 12} }{2}$

$x=\frac{-10+-\sqrt{88} }{2}$

$x=-5+-\sqrt{22}$

Therefore, the answer is [ x = -5 ± √22 ]

Best of Luck!