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3 years ago

X² +10x+3=0how do I slove it with the quadratic formula?

Mathematics

2 answers:

puteri [66]3 years ago

7 0

Answer:

Step-by-step explanation:

Naddik [55]3 years ago

4 0

The equation is already in standard form [ ax² + bx + c = y ] so we can find the values of each variable.

a = 1

b = 10

c = 3

y = 0

Quadratic formula: $x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

Solve using the formula:

$x=\frac{-10+-\sqrt{10^2-4(1)(3)} }{2(1)}$

$x=\frac{-10+-\sqrt{100 - 12} }{2}$

$x=\frac{-10+-\sqrt{88} }{2}$

$x=-5+-\sqrt{22}$

Therefore, the answer is [ x = -5 ± √22 ]

Best of Luck!

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Answer:

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Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

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Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

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On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

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X² +10x+3=0how do I slove it with the quadratic formula?​

X² +10x+3=0how do I slove it with the quadratic formula?