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Verdich [7]
3 years ago
5

Harry's motorboat can make an average of 8 miles per hour. one day he sets out for a trip, only to have the motor break down. ha

rry rows back at two miles an hour. when he reaches his dock, he finds that he has been gone 5 hours. how far has he rowed?
Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
He rowed 10 miles in total. YOU'RE WELCOME :D
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Whats The square root of 69?
Ber [7]

Square root of 69= 8.306624


check the answer

8.3^2= 8.3*8.3= 68.89

now round 68.89 = 69


I hope that's help!

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3 years ago
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In a shoe store window, Sandy sees a sign announcing 25% off all sandals in stock. She finds a pair she likes that was originall
kompoz [17]
The answer is A. She will pay 11.25
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3 years ago
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Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
You and a friend go to super taco for lunch. You order three soft tacos and three burritos and your bill totals $11.25. Your fri
Phoenix [80]

Soft tacos are going to be $1.25, and burritos are going to be $2.50

3 0
3 years ago
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1.7 m+ 3.7 m +3.7 m +3 m +5.9 m​
FinnZ [79.3K]

answer:

18 m

step-by-step explanation:

  • simply add up all the numbers given
  • 1.7 + 3.7 + 3.7 + 3 + 5.9 = 18
  • then, put the units given
3 0
3 years ago
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