Question

Jamal simplified ...

Answer 1

$\bf \sqrt{75x^5y^8}\qquad \begin{cases} 75=3\cdot 25\\ \qquad 3\cdot 5^2\\ x^5=x^{4+1}\\ \qquad x^4x^1\\ \qquad (x^2)^2x\\ y^8=y^{4\cdot 2}\\ \qquad (y^4)^2 \end{cases}\implies \sqrt{3\cdot 5^2\cdot (x^2)^2x(y^4)^2} \\\\\\ 5x^2y^4\sqrt{3x}$