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stich3 [128]
3 years ago
14

You can use the _______ of a quadratic equation to determine the number and type of solutions

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer: Discriminant.


Step-by-step explanation:

1. The quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. And the discriminant is inside the square root:

b^{2}-4ac

2. Then, if the discriminant is negative, the quadratic equation does not have real solutions, it has two imaginary solutions. If the discriminant is zero the quadratic has one solution. If the discriminant is positive, the quadratic equation has two distinct solutions.


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(x³ + ³) / (x - y)<br> Do not include parentheses in your answer.
Lubov Fominskaja [6]

The simplified expression of \frac{x^3 + (-y)^3}{(x - y} is x^2+xy+y^2

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

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<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x^3 + (-y)^3}{(x - y}

Open the inner bracket

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